~ruther/ctu-fee-eoa

ref: 914ee761437025cc3ab6fc0fa3bfc37cd0c68225 ctu-fee-eoa/codes/tsp_hw01/src/binary_string_representation.rs -rw-r--r-- 6.1 KiB
914ee761 — Rutherther feat: split params out of PerturbationOperator to allow for non-'static PerturbationOperator a month ago
                                                                                
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use nalgebra::{allocator::Allocator, DefaultAllocator, Dim, OVector, U1};
use eoa_lib::{binary_string::BinaryString, fitness::FitnessFunction};
use thiserror::Error;
use crate::tsp::{NodePermutation, TSPInstance};

impl<'a, DIn: Dim, DOut: Dim> FitnessFunction for TSPBinaryStringWrapper<'a, DIn, DOut>
where
    DefaultAllocator: Allocator<DIn>,
    DefaultAllocator: Allocator<DOut>,
    DefaultAllocator: Allocator<DOut, DOut>,
{
    type In = BinaryString<DIn>;
    type Out = f64;
    type Err = DimensionMismatch;

    fn fit(self: &Self, inp: &Self::In) -> Result<Self::Out, Self::Err> {
        Ok(self.instance.fit(&self.to_permutation(inp)?).unwrap())
    }
}

pub struct TSPBinaryStringWrapper<'a, DIn: Dim, DOut: Dim>
where
    DOut: Dim,
    DefaultAllocator: Allocator<DOut, DOut>
{
    instance: &'a TSPInstance<DOut>,
    dim_in: DIn,
    dim_out: DOut,
}

impl<'a, DIn: Dim, DOut: Dim> TSPBinaryStringWrapper<'a, DIn, DOut>
where
    DOut: Dim,
    DefaultAllocator: Allocator<DOut, DOut>,
    DefaultAllocator: Allocator<DIn>,
    DefaultAllocator: Allocator<DOut>,
{
    pub fn new(
        instance: &'a TSPInstance<DOut>,
        dim_in: DIn,
        dim_out: DOut
    ) -> Result<Self, DimensionMismatch> {
        let res = Self {
            instance,
            dim_in,
            dim_out
        };

        if dim_out.value() * (dim_out.value() - 1) / 2 != dim_in.value() {
            Err(DimensionMismatch::Mismatch)
        } else {
            Ok(res)
        }
    }

    pub fn to_permutation(&self, inp: &BinaryString<DIn>) -> Result<NodePermutation<DOut>, DimensionMismatch> {
        let nodes = self.dim_out.value();

        if inp.vec().shape_generic().0.value() != self.dim_in.value() {
            return Err(DimensionMismatch::Mismatch);
        }

        // Count how many nodes each node comes after (precedence count)
        let mut precedence_count = OVector::<usize, DOut>::zeros_generic(self.dim_out, U1);

        let mut in_index = 0usize;
        for i in 0..self.dim_out.value() {
            for j in i+1..nodes {
                if in_index >= inp.vec.len() {
                    return Err(DimensionMismatch::Mismatch);
                }

                if inp.vec[in_index] == 1 {
                    // i comes before j, so j has one more predecessor
                    precedence_count[j] += 1;
                } else {
                    // j comes before i, so i has one more predecessor
                    precedence_count[i] += 1;
                }

                in_index += 1;
            }
        }

        if in_index != inp.vec.len() {
            return Err(DimensionMismatch::Mismatch);
        }

        let mut result = OVector::from_iterator_generic(
            self.dim_out,
            U1,
            0..nodes
        );

        result
            .as_mut_slice()
            .sort_by_key(|&node| precedence_count[node]);

        Ok(NodePermutation { permutation: result })
    }
}

#[derive(Error, Debug)]
pub enum DimensionMismatch {
    #[error("The input dimension should be equal to half matrix NxN where the output is N")]
    Mismatch
}

#[cfg(test)]
mod tests {
    use super::*;
    use nalgebra::{Const, SVector, U15, U6};
    use eoa_lib::binary_string::BinaryString;

    #[test]
    fn test_binary_string_representation() {
        // x 0 1 2 3 4 5
        // 0 0 0 0 0 0 0
        // 1 1 0 0 0 0 0
        // 2 1 1 0 0 0 0
        // 3 1 1 1 0 0 0
        // 4 1 1 1 1 0 0
        // 5 1 1 1 1 1 0

        // x 0 1 2 3 4 5
        // 0   0 0 0 0 0
        // 1     0 0 0 0
        // 2       0 0 0
        // 3         0 0
        // 4           0
        // 5

        // 6 nodes
        // length of binary string: 5 + 4 + 3 + 2 + 1 = 15

        let tsp = TSPInstance::new_const(
            vec![
                (0.0, 0.0),
                (0.0, 0.0),
                (0.0, 0.0),
                (0.0, 0.0),
                (0.0, 0.0),
                (0.0, 0.0),
            ]
        );
        let converter = TSPBinaryStringWrapper::new(
            &tsp,
            U15,
            U6
        ).unwrap();

        let binary_string_ordering = BinaryString::<U15>::new(vec![1; 15]);

        let mut expected_permutation = vec![0, 1, 2, 3, 4, 5];

        let mut permutation = converter.to_permutation(&binary_string_ordering)
            .unwrap();

        assert_eq!(
            expected_permutation,
            permutation.permutation.as_mut_slice().to_vec()
        );

        let binary_string_ordering = BinaryString::<U15>::new(vec![0; 15]);
        expected_permutation.reverse();

        let mut permutation = converter.to_permutation(&binary_string_ordering)
            .unwrap();

        assert_eq!(
            expected_permutation,
            permutation.permutation.as_mut_slice().to_vec()
        )
    }

    #[test]
    fn test_nontrivial_binary_string_representation() {
        // x 0 1 2 3 4 5
        // 0 0 1 0 0 0 0
        // 1 0 0 0 0 0 0
        // 2 1 1 0 0 0 1
        // 3 1 1 1 0 0 0
        // 4 1 1 1 1 0 0
        // 5 1 1 0 1 1 0

        // x 0 1 2 3 4 5
        // 0   0 0 0 0 0
        // 1     0 0 0 0
        // 2       1 1 1
        // 3         0 0
        // 4           1
        // 5

        // 6 nodes
        // length of binary string: 5 + 4 + 3 + 2 + 1 = 15

        let tsp = TSPInstance::new_const(
            vec![
                (0.0, 0.0),
                (0.0, 0.0),
                (0.0, 0.0),
                (0.0, 0.0),
                (0.0, 0.0),
                (0.0, 0.0),
            ]
        );
        let converter = TSPBinaryStringWrapper::new(
            &tsp,
            U15,
            U6
        ).unwrap();

        let mut binary_string_ordering = BinaryString::<U15>::new(vec![0; 15]);
        binary_string_ordering.vec[9] = 1;
        binary_string_ordering.vec[10] = 1;
        binary_string_ordering.vec[11] = 1;
        binary_string_ordering.vec[14] = 1;

        let expected_permutation = vec![2, 4, 5, 3, 1, 0];

        let mut permutation = converter.to_permutation(&binary_string_ordering)
            .unwrap();

        assert_eq!(
            expected_permutation,
            permutation.permutation.as_mut_slice().to_vec()
        );
    }
}