~ruther/guix-local

726a78b8bc490757736edf1187d479aac335a783 — Efraim Flashner 5 years ago 0d88866
gnu: Add julia-pyplot.

* gnu/packages/julia-xyz.scm (julia-pyplot): New variable.
1 files changed, 29 insertions(+), 0 deletions(-)

M gnu/packages/julia-xyz.scm
M gnu/packages/julia-xyz.scm => gnu/packages/julia-xyz.scm +29 -0
@@ 3281,6 3281,35 @@ types between Julia and Python), define Python classes from Julia methods, and
share large data structures between Julia and Python without copying them.")
    (license license:expat)))

(define-public julia-pyplot
  (package
    (name "julia-pyplot")
    (version "2.10.0")
    (source
      (origin
        (method git-fetch)
        (uri (git-reference
               (url "https://github.com/JuliaPy/PyPlot.jl")
               (commit (string-append "v" version))))
        (file-name (git-file-name name version))
        (sha256
         (base32 "007zs0imfgs69f30pp2a3rc93kl0qiq7qjx6ig35z4wzkmps4skd"))))
    (build-system julia-build-system)
    (propagated-inputs
     `(("julia-colors" ,julia-colors)
       ("julia-latexstrings" ,julia-latexstrings)
       ("julia-pycall" ,julia-pycall)
       ("julia-versionparsing" ,julia-versionparsing)
       ;; python-matplotlib is expected to be available at runtime.
       ("python-matplotlib" ,python-matplotlib)))
    (home-page "https://github.com/JuliaPy/PyPlot.jl")
    (synopsis "Plotting for Julia based on matplotlib.pyplot")
    (description "This package provides a Julia interface to the Matplotlib
plotting library from Python, and specifically to the @code{matplotlib.pyplot}
module.  PyPlot uses the Julia PyCall package to call Matplotlib directly from
Julia with little or no overhead (arrays are passed without making a copy).")
    (license license:expat)))

(define-public julia-quadgk
  (package
    (name "julia-quadgk")